3x^2-65x+272=0

Solution for 3x^2-65x+272=0 equation:

3x^2-65x+272=0

a = 3; b = -65; c = +272;
Δ = b2-4ac
Δ = -652-4·3·272
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-31}{2*3}=\frac{34}{6}
=5+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+31}{2*3}=\frac{96}{6}
=16
$